What is the derivative of y=(14)/(ln(x)) ?

The derivative of y=(14)/(ln(x)) is -(14)/(xln^2(x))

What is the first derivative of y=(14)/(ln(x)) ?

The first derivative of y=(14)/(ln(x)) is -(14)/(xln^2(x))

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derivative of

y = \frac{14}{ln ( x )}

- \frac{14}{x ln ^{2} ( x )}

Solution steps

\frac{d}{d x} (\frac{14}{ln ( x )})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 14 \frac{d}{d x} (\frac{1}{ln ( x )})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 14 \frac{d}{d x} (ln^{- 1} (x))

Apply the chain rule:

- \frac{1}{( ln ( x ) ) ^{2}} \frac{d}{d x} (ln (x))

= - \frac{1}{( ln ( x ) ) ^{2}} \frac{d}{d x} (ln (x))

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= 14 (- \frac{1}{( ln ( x ) ) ^{2}} \cdot \frac{1}{x})

Simplify

14 (- \frac{1}{ln ^{2} ( x )} \cdot \frac{1}{x}) : - \frac{14}{x ln ^{2} ( x )}

= - \frac{14}{x ln ^{2} ( x )}

e^{y} d x - e^{- x} d y = 0

e^{\frac{8}{9} x}

(- 1, - 5), (3, - 7)

\frac{d}{d x} (e^{x} - 2)

\int_{- 2}^{0} (x + 2) d x

What is the derivative of y=(14)/(ln(x)) ?
The derivative of y=(14)/(ln(x)) is -(14)/(xln^2(x))
What is the first derivative of y=(14)/(ln(x)) ?
The first derivative of y=(14)/(ln(x)) is -(14)/(xln^2(x))