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Popular >

(y^')/(x^3+y)= 1/x

Solution

\frac{y ^{^{'}}}{x ^{3} + y} = \frac{1}{x}

Solution

y = \frac{x ^{3}}{2} + c_{1} x

Solution steps

\frac{y ^{'} ( x )}{x ^{3} + y} = \frac{1}{x}

Solve linear ODE:

y = \frac{x ^{3}}{2} + c_{1} x

y = \frac{x ^{3}}{2} + c_{1} x

Popular Examples

integral of (cotan(ln(x)))/(2x)

\int \frac{co tan ( ln ( x ) )}{2 x}

(\partial ^2)/(\partial y^2)(x^3+3xy^2)

\frac{\partial ^{2}}{\partial y ^{2}} (x^{3} + 3 x y^{2})

limit as x approaches 0-of 2/(e^x+1)

x \to 0 - lim (\frac{2}{e ^{x} + 1})

tangent of sqrt(x) 1/(sqrt(x^3))tangent of

x \frac{1}{x ^{3}}

(dy)/(dx)+3y=e^{-3x}

\frac{d y}{d x} + 3 y = e^{- 3 x}

Frequently Asked Questions (FAQ)

What is the solution for (y^')/(x^3+y)= 1/x ?
The solution for (y^')/(x^3+y)= 1/x is y=(x^3)/2+c_{1}x