What is the derivative of cy^{-3} ?

The derivative of cy^{-3} is -(3c)/(y^4)

What is the first derivative of cy^{-3} ?

The first derivative of cy^{-3} is -(3c)/(y^4)

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derivative of

c y^{- 3}

- \frac{3 c}{y ^{4}}

Solution steps

\frac{d}{d y} (c y^{- 3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= c \frac{d}{d y} (y^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= c (- 3 y^{- 3 - 1})

Simplify

c (- 3 y^{- 3 - 1}) : - \frac{3 c}{y ^{4}}

= - \frac{3 c}{y ^{4}}

f (x) = ln (x + 5)

\frac{70}{x}

\int sin (30 x) d x

n = 1 \sum \infty \frac{1}{n + 3}

\int_{0}^{5} ln (x) d x

What is the derivative of cy^{-3} ?
The derivative of cy^{-3} is -(3c)/(y^4)
What is the first derivative of cy^{-3} ?
The first derivative of cy^{-3} is -(3c)/(y^4)