What is (\partial)/(\partial x)(2cos(pix)) ?

The answer to (\partial)/(\partial x)(2cos(pix)) is -2pisin(pix)

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(\partial)/(\partial x)(2cos(pix))

\frac{\partial}{\partial x} (2 cos (π x))

- 2 π sin (π x)

Solution steps

\frac{\partial}{\partial x} (2 cos (π x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{\partial}{\partial x} (cos (π x))

Apply the chain rule:

- sin (π x) \frac{\partial}{\partial x} (π x)

= - sin (π x) \frac{\partial}{\partial x} (π x)

\frac{\partial}{\partial x} (π x) = π

= 2 (- sin (π x) π)

Simplify

= - 2 π sin (π x)

\int \frac{x ^{2} - 3 x + 7}{x + 5} d x

lo g_{2} (x^{2} + 1)

f (x) = \frac{x}{x + 5}

y = 9 - 4 x, at x = - 1

\int_{0}^{\frac{π}{4}} 9 tan^{3} (x) d x

What is (\partial)/(\partial x)(2cos(pix)) ?
The answer to (\partial)/(\partial x)(2cos(pix)) is -2pisin(pix)