What is the solution for (dy)/(dx)= 1/(2y+1) ?

The solution for (dy)/(dx)= 1/(2y+1) is y=(-1+sqrt(1-4(-c_{1)-x)})/2 ,y=(-1-sqrt(1-4(-c_{1)-x)})/2

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(dy)/(dx)= 1/(2y+1)

\frac{d y}{d x} = \frac{1}{2 y + 1}

y = \frac{- 1 + 1 - 4 ( - c _{1} - x )}{2}, y = \frac{- 1 - 1 - 4 ( - c _{1} - x )}{2}

Solution steps

\frac{d y}{d x} = \frac{1}{2 y + 1}

Solve separable ODE:

y = \frac{- 1 + 1 - 4 ( - c _{1} - x )}{2}, y = \frac{- 1 - 1 - 4 ( - c _{1} - x )}{2}

y = \frac{- 1 + 1 - 4 ( - c _{1} - x )}{2}, y = \frac{- 1 - 1 - 4 ( - c _{1} - x )}{2}

\int \frac{1}{136} x^{3} d x

y = \frac{- 9 e ^{4 x}}{8 x + 3}

\int \frac{( x - 2 )}{x - 1} d x

n = 0 \sum \infty \frac{1}{n ^{2} + n}

\int \frac{x}{x ^{2} - 6 x} d x

What is the solution for (dy)/(dx)= 1/(2y+1) ?
The solution for (dy)/(dx)= 1/(2y+1) is y=(-1+sqrt(1-4(-c_{1)-x)})/2 ,y=(-1-sqrt(1-4(-c_{1)-x)})/2