What is (\partial ^2)/(\partial y^2)(x^3+3xy^2) ?

The answer to (\partial ^2)/(\partial y^2)(x^3+3xy^2) is 6x

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(\partial ^2)/(\partial y^2)(x^3+3xy^2)

\frac{\partial ^{2}}{\partial y ^{2}} (x^{3} + 3 x y^{2})

6 x

Solution steps

\frac{\partial ^{2}}{\partial y ^{2}} (x^{3} + 3 x y^{2})

\frac{\partial}{\partial y} (x^{3} + 3 x y^{2}) = 6 x y

= \frac{\partial}{\partial y} (6 x y)

\frac{\partial}{\partial y} (6 x y) = 6 x

= 6 x

x \to 0 - lim (\frac{2}{e ^{x} + 1})

x \frac{1}{x ^{3}}

\frac{d y}{d x} + 3 y = e^{- 3 x}

\frac{2 x - 5}{x ^{2} - 1}

x \to - 1 lim (arctan (x))

What is (\partial ^2)/(\partial y^2)(x^3+3xy^2) ?
The answer to (\partial ^2)/(\partial y^2)(x^3+3xy^2) is 6x