What is the limit as x approaches 1+of (x+8)/(x-1) ?

The limit as x approaches 1+of (x+8)/(x-1) is infinity

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limit as x approaches 1+of (x+8)/(x-1)

x \to 1 + lim (\frac{x + 8}{x - 1})

\infty

Solution steps

x \to 1 + lim (\frac{x + 8}{x - 1})

\frac{x + 8}{x - 1} = (x + 8) \frac{1}{x - 1}

= x \to 1 + lim ((x + 8) \frac{1}{x - 1})

x \to a lim [f (x) \cdot g (x)] = x \to a lim f (x) \cdot x \to a lim g (x)

With the exception of indeterminate form

= x \to 1 + lim (x + 8) \cdot x \to 1 + lim (\frac{1}{x - 1})

x \to 1 + lim (x + 8) = 9

x \to 1 + lim (\frac{1}{x - 1}) = \infty

= 9 \cdot \infty

Apply Infinity Property:

c \cdot \infty = \infty

= \infty

\int - \frac{1}{t - 2} d t

y^{^{'}} + 4 x y^{2} = 0

\frac{d y}{1 + 4 y ^{2}} = - \frac{x d x}{1 + x ^{4}}

\int \frac{5 x - 1}{( x + 1 ) ( x - 2 )} d x

x^{9}, at x = 1

What is the limit as x approaches 1+of (x+8)/(x-1) ?
The limit as x approaches 1+of (x+8)/(x-1) is infinity