What is the tangent of f(x)=sqrt(10x),(10,10) ?

The tangent of f(x)=sqrt(10x),(10,10) is y= 1/2 x+5

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tangent of f(x)=sqrt(10x),(10,10)

tangent of

f (x) = 10 x, (10, 10)

y = \frac{1}{2} x + 5

Solution steps

Find the slope of

f (x) = 10 x : \frac{df ( x )}{d x} = \frac{5}{2 x}

Compute the slope of

f (x) = 10 x

(10, 10) : m = \frac{1}{2}

Find the line with slope m=

\frac{1}{2}

and passing through

(10, 10) : y = \frac{1}{2} x + 5

y = \frac{1}{2} x + 5

\int \frac{x - 1}{x ^{2} - 4 x + 5} d x

\frac{d y}{d x} + y = - 1, y (0) = 1

2 x - 3

f (x) = 3 x + 4, at x = 4

f (x) = x^{4} - 32 x^{2} + 256, at (1,)

What is the tangent of f(x)=sqrt(10x),(10,10) ?
The tangent of f(x)=sqrt(10x),(10,10) is y= 1/2 x+5