What is the solution for y^'+9x^{-1}y=x^7,y(1)=8 ?

The solution for y^'+9x^{-1}y=x^7,y(1)=8 is y=(x^8)/(17)+(135)/(17x^9)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'+9x^{-1}y=x^7,y(1)=8

y^{^{'}} + 9 x^{- 1} y = x^{7}, y (1) = 8

y = \frac{x ^{8}}{17} + \frac{135}{17 x ^{9}}

Solution steps

y^{'} (x) + 9 x^{- 1} y = x^{7}

Solve linear ODE:

y = \frac{x ^{8}}{17} + \frac{135}{17 x ^{9}}

y = \frac{x ^{8}}{17} + \frac{135}{17 x ^{9}}

\int (5 x - 3)^{2} (2 x - 1) d x

x \to 0 lim (x ln (1 + \frac{1}{x}))

\frac{- 3 x + 12}{2 6 - x}

f (x) = (tan (\frac{1}{x}))^{s e c (\frac{1}{x})}

\int \frac{x}{( 1 + x ^{2} ) ^{y}} d x

What is the solution for y^'+9x^{-1}y=x^7,y(1)=8 ?
The solution for y^'+9x^{-1}y=x^7,y(1)=8 is y=(x^8)/(17)+(135)/(17x^9)