What is area y=(10)/(x^2-2x-24),x=-2,x=2 ?

The answer to area y=(10)/(x^2-2x-24),x=-2,x=2 is ln(6)

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area y=(10)/(x^2-2x-24),x=-2,x=2

area

y = \frac{10}{x ^{2} - 2 x - 24}, x = - 2, x = 2

ln (6)

Decimal Notation

1.79175 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{2} \frac{10}{∣ x ^{2} - 2 x - 24 ∣} d x

Solve

\int_{- 2}^{2} \frac{10}{∣ x ^{2} - 2 x - 24 ∣} d x : ln (6)

The area is:

= ln (6)

h^{^{'}} = 6 - 5 cos (\frac{π}{15} t)

\int \frac{1 - sin ( x )}{x + cos ( x )} d x

x \to + (- 1) lim (x)

\frac{d}{d x} (- \frac{16}{x ^{3}})

y = \frac{3}{x}, y = 12 x, y = \frac{1}{3} x

What is area y=(10)/(x^2-2x-24),x=-2,x=2 ?
The answer to area y=(10)/(x^2-2x-24),x=-2,x=2 is ln(6)