What is the derivative of-(16/(x^3)) ?

The derivative of-(16/(x^3)) is (48)/(x^4)

What is the first derivative of-(16/(x^3)) ?

The first derivative of-(16/(x^3)) is (48)/(x^4)

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\frac{d}{d x} (- \frac{16}{x ^{3}})

\frac{48}{x ^{4}}

Solution steps

\frac{d}{d x} (- \frac{16}{x ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 16 \frac{d}{d x} (\frac{1}{x ^{3}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - 16 \frac{d}{d x} (x^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 16 (- 3 x^{- 3 - 1})

Simplify

- 16 (- 3 x^{- 3 - 1}) : \frac{48}{x ^{4}}

= \frac{48}{x ^{4}}

y = \frac{3}{x}, y = 12 x, y = \frac{1}{3} x

h \to 0 lim (\frac{( x - h ) - x}{h})

f (x) = sec (- 4 x^{2} - 3 x + 2)

\frac{d}{d x} (e^{- \frac{1}{x ^{7}}})

x \to 0 lim (tan (x^{2}) ln (x))

What is the derivative of-(16/(x^3)) ?
The derivative of-(16/(x^3)) is (48)/(x^4)
What is the first derivative of-(16/(x^3)) ?
The first derivative of-(16/(x^3)) is (48)/(x^4)