What is the solution for x^2+3xy+x(dy)/(dx)=0 ?

The solution for x^2+3xy+x(dy)/(dx)=0 is y=-(3x-1)/9+(c_{1})/(e^{3x)}

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x^2+3xy+x(dy)/(dx)=0

x^{2} + 3 x y + x \frac{d y}{d x} = 0

y = - \frac{3 x - 1}{9} + \frac{c _{1}}{e ^{3 x}}

Solution steps

x^{2} + 3 x y + x \frac{d y}{d x} = 0

Solve linear ODE:

y = - \frac{3 x - 1}{9} + \frac{c _{1}}{e ^{3 x}}

y = - \frac{3 x - 1}{9} + \frac{c _{1}}{e ^{3 x}}

y = 16 - x^{2}, y = 0, x = - 2, x = 3

\frac{7}{s ^{3} + 2 s ^{2} + 9 s + 18}

\int (\frac{3}{x ^{\frac{1}{3}}} - 3 x^{\frac{2}{3}}) d x

\frac{36 x}{x ^{2} + 36}

\frac{d}{d x} (- 4 e^{12 x})

What is the solution for x^2+3xy+x(dy)/(dx)=0 ?
The solution for x^2+3xy+x(dy)/(dx)=0 is y=-(3x-1)/9+(c_{1})/(e^{3x)}