What is area y=16-x^2,y=0,x=-2,x=3 ?

The answer to area y=16-x^2,y=0,x=-2,x=3 is 205/3

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area y=16-x^2,y=0,x=-2,x=3

area

y = 16 - x^{2}, y = 0, x = - 2, x = 3

\frac{205}{3}

Decimal Notation

68.33333 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{3} - x^{2} + 16 d x

Solve

\int_{- 2}^{3} - x^{2} + 16 d x : \frac{205}{3}

The area is:

= \frac{205}{3}

\frac{7}{s ^{3} + 2 s ^{2} + 9 s + 18}

\int (\frac{3}{x ^{\frac{1}{3}}} - 3 x^{\frac{2}{3}}) d x

\frac{36 x}{x ^{2} + 36}

\frac{d}{d x} (- 4 e^{12 x})

\int (3^{4} + x^{15}) d x

What is area y=16-x^2,y=0,x=-2,x=3 ?
The answer to area y=16-x^2,y=0,x=-2,x=3 is 205/3