What is the integral of 4cos(θ)sin(θ) ?

The integral of 4cos(θ)sin(θ) is 2sin^2(θ)+C

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integral of 4cos(θ)sin(θ)

\int 4 cos (θ) sin (θ) d θ

2 sin^{2} (θ) + C

Solution steps

\int 4 cos (θ) sin (θ) d θ

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int cos (θ) sin (θ) d θ

Apply u-substitution

: \int u d u

= 4 \cdot \int u d u

Apply the Power Rule

: \frac{u ^{2}}{2}

= 4 \cdot \frac{u ^{2}}{2}

Substitute back

u = sin (θ)

= 4 \cdot \frac{sin ^{2} ( θ )}{2}

Simplify

4 \cdot \frac{sin ^{2} ( θ )}{2} : 2 sin^{2} (θ)

= 2 sin^{2} (θ)

Add a constant to the solution

= 2 sin^{2} (θ) + C

x \to 0 + lim (\frac{e ^{x} - 1}{x})

\frac{1}{( s + 1 ) ^{\frac{1}{2}}}

(- 6, 4), (- 1, 4)

\frac{d}{d x} (\frac{x ^{n - 1}}{n})

\int_{x}^{2 x} y d y

What is the integral of 4cos(θ)sin(θ) ?
The integral of 4cos(θ)sin(θ) is 2sin^2(θ)+C