What is the integral from x to 2x of y ?

The integral from x to 2x of y is 2x^2-(x^2)/2

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integral from x to 2x of y

\int_{x}^{2 x} y d y

2 x^{2} - \frac{x ^{2}}{2}

Solution steps

\int_{x}^{2 x} y d y

Apply the Power Rule

: [\frac{y ^{2}}{2}]_{x}^{2 x}

= [\frac{y ^{2}}{2}]_{x}^{2 x}

Compute the boundaries:

2 x^{2} - \frac{x ^{2}}{2}

= 2 x^{2} - \frac{x ^{2}}{2}

n = 0 \sum \infty \frac{n ^{3}}{5 ^{n}}

\frac{\partial}{\partial x} (2 x^{3} y + sin (x^{2}))

f (x) = \frac{4 x}{x ^{2} - 5}, (3, 3)

x \to 7 lim (\frac{x + 2}{x - 7})

\int \frac{e ^{3 x} + 1}{e ^{2 x}} d x

What is the integral from x to 2x of y ?
The integral from x to 2x of y is 2x^2-(x^2)/2