What is the limit as x approaches 7 of (x+2)/(x-7) ?

The limit as x approaches 7 of (x+2)/(x-7) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 7 of (x+2)/(x-7)

x \to 7 lim (\frac{x + 2}{x - 7})

diverges

Solution steps

x \to 7 lim (\frac{x + 2}{x - 7})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 7 + lim (\frac{x + 2}{x - 7}) = \infty

x \to 7 - lim (\frac{x + 2}{x - 7}) = - \infty

= diverges

\int \frac{e ^{3 x} + 1}{e ^{2 x}} d x

\int_{0}^{1} \frac{x - 6}{x ^{2} - 5 x + 6} d x

\frac{d y}{d x} - e^{8 x + y} = 0

\int x \cdot sin (2 a x) d x

cos (e^{x^{2 c o s (x)}})

What is the limit as x approaches 7 of (x+2)/(x-7) ?
The limit as x approaches 7 of (x+2)/(x-7) is diverges