What is the derivative of f(x)=(3x^2+3x-1)^4 ?

The derivative of f(x)=(3x^2+3x-1)^4 is 4(3x^2+3x-1)^3(6x+3)

What is the first derivative of f(x)=(3x^2+3x-1)^4 ?

The first derivative of f(x)=(3x^2+3x-1)^4 is 4(3x^2+3x-1)^3(6x+3)

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derivative of

f (x) = (3 x^{2} + 3 x - 1)^{4}

4 (3 x^{2} + 3 x - 1)^{3} (6 x + 3)

Solution steps

\frac{d}{d x} ((3 x^{2} + 3 x - 1)^{4})

Apply the chain rule:

4 (3 x^{2} + 3 x - 1)^{3} \frac{d}{d x} (3 x^{2} + 3 x - 1)

= 4 (3 x^{2} + 3 x - 1)^{3} \frac{d}{d x} (3 x^{2} + 3 x - 1)

\frac{d}{d x} (3 x^{2} + 3 x - 1) = 6 x + 3

= 4 (3 x^{2} + 3 x - 1)^{3} (6 x + 3)

\int x \cdot sin (x) \cdot cos (x) d x

y = ln (\frac{4}{x})

f (x) = (2 x - 6)^{4} (x^{2} + x + 1)^{5}

y = x e - 0.1 x, y = 0, x = 3

\frac{\partial}{\partial y} (\frac{x}{y} + e^{y})

What is the derivative of f(x)=(3x^2+3x-1)^4 ?
The derivative of f(x)=(3x^2+3x-1)^4 is 4(3x^2+3x-1)^3(6x+3)
What is the first derivative of f(x)=(3x^2+3x-1)^4 ?
The first derivative of f(x)=(3x^2+3x-1)^4 is 4(3x^2+3x-1)^3(6x+3)