What is the derivative of y=ln(4/x) ?

The derivative of y=ln(4/x) is -1/x

What is the first derivative of y=ln(4/x) ?

The first derivative of y=ln(4/x) is -1/x

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derivative of

y = ln (\frac{4}{x})

- \frac{1}{x}

Solution steps

\frac{d}{d x} (ln (\frac{4}{x}))

Apply the chain rule:

\frac{1}{\frac{4}{x}} \frac{d}{d x} (\frac{4}{x})

= \frac{1}{\frac{4}{x}} \frac{d}{d x} (\frac{4}{x})

\frac{d}{d x} (\frac{4}{x}) = - \frac{4}{x ^{2}}

= \frac{1}{\frac{4}{x}} (- \frac{4}{x ^{2}})

Simplify

\frac{1}{\frac{4}{x}} (- \frac{4}{x ^{2}}) : - \frac{1}{x}

= - \frac{1}{x}

f (x) = (2 x - 6)^{4} (x^{2} + x + 1)^{5}

y = x e - 0.1 x, y = 0, x = 3

\frac{\partial}{\partial y} (\frac{x}{y} + e^{y})

f (x) = - 3 cos (x), at x = \frac{3 π}{4}

\frac{d}{d x} (sin (w x))

What is the derivative of y=ln(4/x) ?
The derivative of y=ln(4/x) is -1/x
What is the first derivative of y=ln(4/x) ?
The first derivative of y=ln(4/x) is -1/x