What is laplacetransform h(t)=t-2 ?

The answer to laplacetransform h(t)=t-2 is 1/(s^2)-2/s

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laplacetransform h(t)=t-2

laplace transform

h (t) = t - 2

\frac{1}{s ^{2}} - \frac{2}{s}

Solution steps

L {t - 2}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= L {t} - L {2}

L {t} : \frac{1}{s ^{2}}

L {2} : \frac{2}{s}

= \frac{1}{s ^{2}} - \frac{2}{s}

\int x (x + 6)^{7} d x

\frac{\partial}{\partial y} (cos (x) + x cos (y) - y)

n = 0 \sum \infty (\frac{2}{4})^{n}

\int 5 x + 12 d x

n = 0 \sum \infty n \cdot (\frac{1}{6})^{n}

What is laplacetransform h(t)=t-2 ?
The answer to laplacetransform h(t)=t-2 is 1/(s^2)-2/s