What is the solution for (dy)/(dx)=3+12x+9y+36xy ?

The solution for (dy)/(dx)=3+12x+9y+36xy is y=-1/3+c_{1}e^{9(2x^2+x)}

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(dy)/(dx)=3+12x+9y+36xy

\frac{d y}{d x} = 3 + 12 x + 9 y + 36 x y

y = - \frac{1}{3} + c_{1} e^{9 (2 x^{2} + x)}

Solution steps

\frac{d y}{d x} = 3 + 12 x + 9 y + 36 x y

Solve linear ODE:

y = - \frac{1}{3} + c_{1} e^{9 (2 x^{2} + x)}

y = - \frac{1}{3} + c_{1} e^{9 (2 x^{2} + x)}

\frac{d}{d x} (\frac{1}{2 x + 9})

\int_{1}^{4} (2 x + 1) d x

\frac{\partial}{\partial x} (\frac{2 s - 3 x}{3 s + 5 x})

x \to - 2 lim (8 + x^{2})

n = 1 \sum \infty (- \frac{1}{2})^{n}

What is the solution for (dy)/(dx)=3+12x+9y+36xy ?
The solution for (dy)/(dx)=3+12x+9y+36xy is y=-1/3+c_{1}e^{9(2x^2+x)}