en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 4 of (2x+1)

Solution

\int_{1}^{4} (2 x + 1) d x

Solution

18

Solution steps

\int_{1}^{4} 2 x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{4} 2 x d x + \int_{1}^{4} 1 d x

\int_{1}^{4} 2 x d x = 15

\int_{1}^{4} 1 d x = 3

= 15 + 3

Simplify

= 18

Popular Examples

(\partial)/(\partial x)((2s-3x)/(3s+5x))

\frac{\partial}{\partial x} (\frac{2 s - 3 x}{3 s + 5 x})

limit as x approaches-2 of sqrt(8+x^2)

x \to - 2 lim (8 + x^{2})

sum from n=1 to infinity of (-1/2)^n

n = 1 \sum \infty (- \frac{1}{2})^{n}

y^{''}-y^'-2y=8,y(0)=0,y^'(0)=5

y^{^{''}} - y^{^{'}} - 2 y = 8, y (0) = 0, y^{^{'}} (0) = 5

limit as x approaches 3 of 4^{x^3}-8x

x \to 3 lim (4^{x^{3}} - 8 x)

Frequently Asked Questions (FAQ)

What is the integral from 1 to 4 of (2x+1) ?
The integral from 1 to 4 of (2x+1) is 18