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Popular >

y^'+1/t y= 1/(t^2)

Solution

y^{^{'}} + \frac{1}{t} y = \frac{1}{t ^{2}}

Solution

y = \frac{ln ( t )}{t} + \frac{c _{1}}{t}

Solution steps

y^{'} (t) + \frac{1}{t} y = \frac{1}{t ^{2}}

Solve linear ODE:

y = \frac{ln ( t )}{t} + \frac{c _{1}}{t}

y = \frac{ln ( t )}{t} + \frac{c _{1}}{t}

Popular Examples

f (x) = x^{2} cos (x)

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\int e^{(- \frac{x}{4})} d x

derivative of x^2+x-8 derivative of

x^{2} + x - 8

integral of 7xarcsin(x)

\int 7 x arcsin (x) d x

limit as x approaches 0 of 9/x-9/(|x|)

x \to 0 lim (\frac{9}{x} - \frac{9}{∣ x ∣})

Frequently Asked Questions (FAQ)

What is the solution for y^'+1/t y= 1/(t^2) ?
The solution for y^'+1/t y= 1/(t^2) is y=(ln(t))/t+(c_{1})/t