What is (\partial)/(\partial v)(ucos(v)) ?

The answer to (\partial)/(\partial v)(ucos(v)) is -usin(v)

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(\partial)/(\partial v)(ucos(v))

\frac{\partial}{\partial v} (u cos (v))

- u sin (v)

Solution steps

\frac{\partial}{\partial v} (u cos (v))

Treat

u

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= u \frac{\partial}{\partial v} (cos (v))

Apply the common derivative:

\frac{\partial}{\partial v} (cos (v)) = - sin (v)

= u (- sin (v))

Simplify

= - u sin (v)

f (x) = 2 x^{2} - 6 x

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\frac{\partial}{\partial x} (ln (\frac{x}{x + 2}))

\int \frac{3 x ^{2} - 2}{x ^{2} - 2 x - 8} d x

What is (\partial)/(\partial v)(ucos(v)) ?
The answer to (\partial)/(\partial v)(ucos(v)) is -usin(v)