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Popular >

y^'=-(2x)/y ,y(1)=10

Solution

y^{^{'}} = - \frac{2 x}{y}, y (1) = 10

Solution

y = - 2 x^{2} + 102

Solution steps

y^{'} (x) = - \frac{2 x}{y}

Solve separable ODE:

y = - 2 x^{2} + 102

y = - 2 x^{2} + 102

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Frequently Asked Questions (FAQ)

What is the solution for y^'=-(2x)/y ,y(1)=10 ?
The solution for y^'=-(2x)/y ,y(1)=10 is y=sqrt(-2x^2+102)