What is the d/(du)(e^ucos(v)) ?

The d/(du)(e^ucos(v)) is cos(v)e^u

What is the first d/(du)(e^ucos(v)) ?

The first d/(du)(e^ucos(v)) is cos(v)e^u

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Popular >

\frac{d}{d u} (e^{u} cos (v))

cos (v) e^{u}

Solution steps

\frac{d}{d u} (e^{u} cos (v))

Treat

v

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= cos (v) \frac{d}{d u} (e^{u})

Apply the common derivative:

\frac{d}{d u} (e^{u}) = e^{u}

= cos (v) e^{u}

2 sin (3 x)

3 (cos (x) ln (x) + \frac{sin ( x )}{x})

\frac{d}{d x} (ln (4 + x^{2}))

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x \to - 1 lim (\frac{x ^{4} - 1}{x + 1})