What is the limit as x approaches-1 of (x^4-1)/(x+1) ?

The limit as x approaches-1 of (x^4-1)/(x+1) is -4

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limit as x approaches-1 of (x^4-1)/(x+1)

x \to - 1 lim (\frac{x ^{4} - 1}{x + 1})

- 4

Solution steps

x \to - 1 lim (\frac{x ^{4} - 1}{x + 1})

Simplify

\frac{x ^{4} - 1}{x + 1} : (x^{2} + 1) (x - 1)

= x \to - 1 lim ((x^{2} + 1) (x - 1))

Plug in the value

x = - 1

= ((- 1)^{2} + 1) (- 1 - 1)

Simplify

((- 1)^{2} + 1) (- 1 - 1) : - 4

= - 4

x \to 0 - lim ((1 - \frac{1}{x})^{x})

\frac{d}{d x} (x^{3} ln (7 x))

f (x) = e^{4 - 5 x} (3 x^{3} - 2)^{6}

y^{^{'}} = 2 x + y, y (0) = 9

y^{^{''}} - y = 10 sin^{2} (x)

What is the limit as x approaches-1 of (x^4-1)/(x+1) ?
The limit as x approaches-1 of (x^4-1)/(x+1) is -4