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Popular >

y^'=2x+y,y(0)=9

Solution

y^{^{'}} = 2 x + y, y (0) = 9

Solution

y = - 2 (x + 1) + 11 e^{x}

Solution steps

y^{'} (x) = 2 x + y

Solve linear ODE:

y = - 2 (x + 1) + 11 e^{x}

y = - 2 (x + 1) + 11 e^{x}

Popular Examples

y^{''}-y=10sin^2(x)

y^{^{''}} - y = 10 sin^{2} (x)

integral of 2^x(2^{-x}+1)

\int 2^{x} (2^{- x} + 1) d x

integral of 1/(x^2+100)

\int \frac{1}{x ^{2} + 100} d x

sum from n=0 to infinity of (1/10)^n

n = 0 \sum \infty (\frac{1}{10})^{n}

laplacetransform 5cos(t/(3000))laplace transform

5 cos (\frac{t}{3000})

Frequently Asked Questions (FAQ)

What is the solution for y^'=2x+y,y(0)=9 ?
The solution for y^'=2x+y,y(0)=9 is y=-2(x+1)+11e^x