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Popular >

derivative of (8x^4-9x^2+4)^4

Solution

derivative of

(8 x^{4} - 9 x^{2} + 4)^{4}

Solution

4 (8 x^{4} - 9 x^{2} + 4)^{3} (32 x^{3} - 18 x)

Solution steps

\frac{d}{d x} ((8 x^{4} - 9 x^{2} + 4)^{4})

Apply the chain rule:

4 (8 x^{4} - 9 x^{2} + 4)^{3} \frac{d}{d x} (8 x^{4} - 9 x^{2} + 4)

= 4 (8 x^{4} - 9 x^{2} + 4)^{3} \frac{d}{d x} (8 x^{4} - 9 x^{2} + 4)

\frac{d}{d x} (8 x^{4} - 9 x^{2} + 4) = 32 x^{3} - 18 x

= 4 (8 x^{4} - 9 x^{2} + 4)^{3} (32 x^{3} - 18 x)

Popular Examples

limit as x approaches 0 of (tan^2(x))/x

x \to 0 lim (\frac{tan ^{2} ( x )}{x})

18y^{''}+3y^'-10y=0

18 y^{^{''}} + 3 y^{^{'}} - 10 y = 0

integral of x^4(x^3+8x^2+7)

\int x^{4} (x^{3} + 8 x^{2} + 7) d x

derivative of 1/(2x+1)derivative of

\frac{1}{2 x + 1}

(\partial)/(\partial x)(-1/(sqrt(x^2+y^2)))

\frac{\partial}{\partial x} (- \frac{1}{x ^{2} + y ^{2}})

Frequently Asked Questions (FAQ)

What is the derivative of (8x^4-9x^2+4)^4 ?
The derivative of (8x^4-9x^2+4)^4 is 4(8x^4-9x^2+4)^3(32x^3-18x)
What is the first derivative of (8x^4-9x^2+4)^4 ?
The first derivative of (8x^4-9x^2+4)^4 is 4(8x^4-9x^2+4)^3(32x^3-18x)