What is the derivative of 1/(2x+1) ?

The derivative of 1/(2x+1) is -2/((2x+1)^2)

What is the first derivative of 1/(2x+1) ?

The first derivative of 1/(2x+1) is -2/((2x+1)^2)

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derivative of

\frac{1}{2 x + 1}

- \frac{2}{( 2 x + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{2 x + 1})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((2 x + 1)^{- 1})

Apply the chain rule:

- \frac{1}{( 2 x + 1 ) ^{2}} \frac{d}{d x} (2 x + 1)

= - \frac{1}{( 2 x + 1 ) ^{2}} \frac{d}{d x} (2 x + 1)

\frac{d}{d x} (2 x + 1) = 2

= - \frac{1}{( 2 x + 1 ) ^{2}} \cdot 2

Simplify

- \frac{1}{( 2 x + 1 ) ^{2}} \cdot 2 : - \frac{2}{( 2 x + 1 ) ^{2}}

= - \frac{2}{( 2 x + 1 ) ^{2}}

\frac{\partial}{\partial x} (- \frac{1}{x ^{2} + y ^{2}})

f (x) = tan^{3} (x + csc (x))

y = 4 - x^{2}

What is the derivative of 1/(2x+1) ?
The derivative of 1/(2x+1) is -2/((2x+1)^2)
What is the first derivative of 1/(2x+1) ?
The first derivative of 1/(2x+1) is -2/((2x+1)^2)