What is the integral of 9x^2-4x+3 ?

The integral of 9x^2-4x+3 is 3x^3-2x^2+3x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 9x^2-4x+3

\int 9 x^{2} - 4 x + 3 d x

3 x^{3} - 2 x^{2} + 3 x + C

Solution steps

\int 9 x^{2} - 4 x + 3 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 9 x^{2} d x - \int 4 x d x + \int 3 d x

\int 9 x^{2} d x = 3 x^{3}

\int 4 x d x = 2 x^{2}

\int 3 d x = 3 x

= 3 x^{3} - 2 x^{2} + 3 x

Add a constant to the solution

= 3 x^{3} - 2 x^{2} + 3 x + C

p \to 4 lim (p^{2} + p + 5)

e^{2 x} cos (5 x)

f (x) = \frac{6 x}{3 + x}

\frac{d}{d x} (144 - x^{2})

1 + x