What is area y=20+x-x^2,x^2-5x ?

The answer to area y=20+x-x^2,x^2-5x is 343/3

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area y=20+x-x^2,x^2-5x

area

y = 20 + x - x^{2}, x^{2} - 5 x

\frac{343}{3}

Decimal Notation

114.33333 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{5} 20 + x - x^{2} - (x^{2} - 5 x) d x

Solve

\int_{- 2}^{5} 20 + x - x^{2} - (x^{2} - 5 x) d x : \frac{343}{3}

The area is:

= \frac{343}{3}

\int (3 x^{5} - 2 x^{3}) d x

cos (tan (x))

\frac{\partial}{\partial x} (e^{x} - x y^{3})

y = - 2 x^{2}

\frac{x ^{2}}{3 + 4 x}