What is the derivative of 0.01x^2 ?

The derivative of 0.01x^2 is 0.02x

What is the first derivative of 0.01x^2 ?

The first derivative of 0.01x^2 is 0.02x

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\frac{d}{d x} (0.01 x^{2})

0.02 x

Solution steps

\frac{d}{d x} (0.01 x^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 0.01 \frac{d}{d x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 0.01 \cdot 2 x^{2 - 1}

Simplify

= 0.02 x

f (x) = 2 - x^{2}

f (x) = 5 + 5 x^{2} - 2 x^{3}, at x = a

x \to 0 lim (\frac{3}{1 + x})

\frac{d}{d x} (x + sin^{2} (x))

(2 x y + x^{2} + x^{4}) d x - (1 + x^{2}) d y = 0

What is the derivative of 0.01x^2 ?
The derivative of 0.01x^2 is 0.02x
What is the first derivative of 0.01x^2 ?
The first derivative of 0.01x^2 is 0.02x