What is the derivative of x+sin^2(x) ?

The derivative of x+sin^2(x) is 1+sin(2x)

What is the first derivative of x+sin^2(x) ?

The first derivative of x+sin^2(x) is 1+sin(2x)

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\frac{d}{d x} (x + sin^{2} (x))

1 + sin (2 x)

Solution steps

\frac{d}{d x} (x + sin^{2} (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (sin^{2} (x))

\frac{d x}{d x} = 1

\frac{d}{d x} (sin^{2} (x)) = sin (2 x)

= 1 + sin (2 x)

(2 x y + x^{2} + x^{4}) d x - (1 + x^{2}) d y = 0

\frac{\partial}{\partial x} (x^{(\frac{y}{z})})

35.4 cos (0.1 (x + 6.2))

x \to 1.01 lim (\frac{1}{x ^{2} - 1})

\frac{d}{d x} (1 + 3 x + 9 x^{2})

What is the derivative of x+sin^2(x) ?
The derivative of x+sin^2(x) is 1+sin(2x)
What is the first derivative of x+sin^2(x) ?
The first derivative of x+sin^2(x) is 1+sin(2x)