What is area y=|x|,y=x^2-1,x=-1,x=1 ?

The answer to area y=|x|,y=x^2-1,x=-1,x=1 is 7/3

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area y=|x|,y=x^2-1,x=-1,x=1

area

y = ∣ x ∣, y = x^{2} - 1, x = - 1, x = 1

\frac{7}{3}

Decimal Notation

2.33333 \dots

Solution steps

Apply the area formula:

\int_{- 1}^{1} ∣ x ∣ - (x^{2} - 1) d x

Solve

\int_{- 1}^{1} ∣ x ∣ - (x^{2} - 1) d x : \frac{7}{3}

The area is:

= \frac{7}{3}

5 t \frac{d y}{d t} - 5 y = t

\frac{\partial}{\partial y} (\frac{y}{x ^{2} + y ^{2}})

\frac{\partial}{\partial x} (x^{3} z + yz)

\frac{d}{d x} (\frac{1}{( 2 x + 1 ) ^{2}})

\frac{d}{d x} (\frac{8}{2 x})

What is area y=|x|,y=x^2-1,x=-1,x=1 ?
The answer to area y=|x|,y=x^2-1,x=-1,x=1 is 7/3