What is the derivative of 8/(2x) ?

The derivative of 8/(2x) is -4/(x^2)

What is the first derivative of 8/(2x) ?

The first derivative of 8/(2x) is -4/(x^2)

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\frac{d}{d x} (\frac{8}{2 x})

- \frac{4}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{8}{2 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{8}{2} \frac{d}{d x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{8}{2} \frac{d}{d x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{8}{2} (- 1 \cdot x^{- 1 - 1})

Simplify

\frac{8}{2} (- 1 \cdot x^{- 1 - 1}) : - \frac{4}{x ^{2}}

= - \frac{4}{x ^{2}}

\frac{\partial}{\partial y} (e^{c o s (x - 2 y)})

\frac{d}{d x} (ln (1 - 8 x))

x \frac{d y}{d x} - y = 3 x^{4}

What is the derivative of 8/(2x) ?
The derivative of 8/(2x) is -4/(x^2)
What is the first derivative of 8/(2x) ?
The first derivative of 8/(2x) is -4/(x^2)