What is the derivative of 6ln(\sqrt[3]{x}) ?

The derivative of 6ln(\sqrt[3]{x}) is 2/(\sqrt[3]{x)x^{2/3}}

What is the first derivative of 6ln(\sqrt[3]{x}) ?

The first derivative of 6ln(\sqrt[3]{x}) is 2/(\sqrt[3]{x)x^{2/3}}

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Solution steps

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

Apply the chain rule:

Simplify

x \frac{d y}{d x} - y = 3 x^{4}

\frac{d}{d x} ((- 3 x + 1)^{3} (2 x - 1)^{4})

\frac{d}{d x} (\frac{1}{( x ^{2} + 3 x + 2 ) ^{3}})

\int cosh (d) x d x

\frac{\partial}{\partial x} (x^{2} y - x)

What is the derivative of 6ln(\sqrt[3]{x}) ?
The derivative of 6ln(\sqrt[3]{x}) is 2/(\sqrt[3]{x)x^{2/3}}
What is the first derivative of 6ln(\sqrt[3]{x}) ?
The first derivative of 6ln(\sqrt[3]{x}) is 2/(\sqrt[3]{x)x^{2/3}}