What is the limit as x approaches 2 of (3x^2-5x-2)/(2x-1) ?

The limit as x approaches 2 of (3x^2-5x-2)/(2x-1) is 0

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limit as x approaches 2 of (3x^2-5x-2)/(2x-1)

x \to 2 lim (\frac{3 x ^{2} - 5 x - 2}{2 x - 1})

0

Solution steps

x \to 2 lim (\frac{3 x ^{2} - 5 x - 2}{2 x - 1})

Plug in the value

x = 2

= \frac{3 \cdot 2 ^{2} - 5 \cdot 2 - 2}{2 \cdot 2 - 1}

Simplify

\frac{3 \cdot 2 ^{2} - 5 \cdot 2 - 2}{2 \cdot 2 - 1} : 0

= 0

y^{2} d x = (2 x y + x^{2}) d y

\int 4 e^{- 5 x} d x

\int (1 - cos (x))^{2} d x

4 - 4 \cdot e^{2 t}

f (x) = \frac{e ^{x}}{x ^{2} + 1}

What is the limit as x approaches 2 of (3x^2-5x-2)/(2x-1) ?
The limit as x approaches 2 of (3x^2-5x-2)/(2x-1) is 0