What is the derivative of 2sin(x)+sin^2(x) ?

The derivative of 2sin(x)+sin^2(x) is 2cos(x)+sin(2x)

What is the first derivative of 2sin(x)+sin^2(x) ?

The first derivative of 2sin(x)+sin^2(x) is 2cos(x)+sin(2x)

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derivative of

2 sin (x) + sin^{2} (x)

2 cos (x) + sin (2 x)

Solution steps

\frac{d}{d x} (2 sin (x) + sin^{2} (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 sin (x)) + \frac{d}{d x} (sin^{2} (x))

\frac{d}{d x} (2 sin (x)) = 2 cos (x)

\frac{d}{d x} (sin^{2} (x)) = sin (2 x)

= 2 cos (x) + sin (2 x)

\frac{\partial}{\partial t} (y + x cos (t))

\int 9 x^{2} d x

y^{^{''}} + 14 y^{^{'}} + 50 y = 0, y (0) = 2, y^{^{'}} (0) = - 17

y = (2 tan^{2} (2 x) - 1)^{\frac{1}{2}}

\frac{\partial}{\partial x} (x (1 - x - 2 y))

What is the derivative of 2sin(x)+sin^2(x) ?
The derivative of 2sin(x)+sin^2(x) is 2cos(x)+sin(2x)
What is the first derivative of 2sin(x)+sin^2(x) ?
The first derivative of 2sin(x)+sin^2(x) is 2cos(x)+sin(2x)