What is (\partial)/(\partial x)(2x^{0.3}y^{0.3}+1) ?

The answer to (\partial)/(\partial x)(2x^{0.3}y^{0.3}+1) is (0.6y^{0.3})/(x^{0.7)}

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(\partial)/(\partial x)(2x^{0.3}y^{0.3}+1)

\frac{\partial}{\partial x} (2 x^{0.3} y^{0.3} + 1)

\frac{0.6 y ^{0.3}}{x ^{0.7}}

Solution steps

\frac{\partial}{\partial x} (2 x^{0.3} y^{0.3} + 1)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x^{0.3} y^{0.3}) + \frac{\partial}{\partial x} (1)

\frac{\partial}{\partial x} (2 x^{0.3} y^{0.3}) = \frac{0.6 y ^{0.3}}{x ^{0.7}}

\frac{\partial}{\partial x} (1) = 0

= \frac{0.6 y ^{0.3}}{x ^{0.7}} + 0

Simplify

= \frac{0.6 y ^{0.3}}{x ^{0.7}}

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What is (\partial)/(\partial x)(2x^{0.3}y^{0.3}+1) ?
The answer to (\partial)/(\partial x)(2x^{0.3}y^{0.3}+1) is (0.6y^{0.3})/(x^{0.7)}