What is the integral of 5cos(x)+4sin(x) ?

The integral of 5cos(x)+4sin(x) is 5sin(x)-4cos(x)+C

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integral of 5cos(x)+4sin(x)

\int 5 cos (x) + 4 sin (x) d x

5 sin (x) - 4 cos (x) + C

Solution steps

\int 5 cos (x) + 4 sin (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 5 cos (x) d x + \int 4 sin (x) d x

\int 5 cos (x) d x = 5 sin (x)

\int 4 sin (x) d x = - 4 cos (x)

= 5 sin (x) - 4 cos (x)

Add a constant to the solution

= 5 sin (x) - 4 cos (x) + C

\frac{\partial}{\partial y} ((x^{3} + (\frac{y}{2}))^{\frac{2}{3}})

\frac{d}{d x} (765480)

y^{^{''}} + y^{^{'}} - 3 y = 0

\int 10 x e x^{2} d x

\frac{d}{d x} (800 - 800 x^{- 1})

What is the integral of 5cos(x)+4sin(x) ?
The integral of 5cos(x)+4sin(x) is 5sin(x)-4cos(x)+C