What is the solution for (dy)/(dx)= 1/(y-x) ?

The solution for (dy)/(dx)= 1/(y-x) is y=\W((c_{1})/(e^{x+1)})+x+1

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(dy)/(dx)= 1/(y-x)

\frac{d y}{d x} = \frac{1}{y - x}

y = W (\frac{c _{1}}{e ^{x + 1}}) + x + 1

Solution steps

\frac{d y}{d x} = \frac{1}{y - x}

Solve exact ODE:

y = W (\frac{c _{1}}{e ^{x + 1}}) + x + 1

y = W (\frac{c _{1}}{e ^{x + 1}}) + x + 1

\int x^{2} - 4 x + 7 d x

x \to - 1 lim (\frac{x ^{2} - 3}{1 - x})

\frac{\partial}{\partial x} (sin (x^{2} y - 4 x y^{2}))

\int \frac{7}{( t ^{2} + 1 ) ^{\frac{3}{2}}} d t

\frac{4}{3 x ^{2}}

What is the solution for (dy)/(dx)= 1/(y-x) ?
The solution for (dy)/(dx)= 1/(y-x) is y=\W((c_{1})/(e^{x+1)})+x+1