What is the derivative of 4/(3x^2) ?

The derivative of 4/(3x^2) is -8/(3x^3)

What is the first derivative of 4/(3x^2) ?

The first derivative of 4/(3x^2) is -8/(3x^3)

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derivative of

\frac{4}{3 x ^{2}}

- \frac{8}{3 x ^{3}}

Solution steps

\frac{d}{d x} (\frac{4}{3 x ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{4}{3} \frac{d}{d x} (\frac{1}{x ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{4}{3} \frac{d}{d x} (x^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{4}{3} (- 2 x^{- 2 - 1})

Simplify

\frac{4}{3} (- 2 x^{- 2 - 1}) : - \frac{8}{3 x ^{3}}

= - \frac{8}{3 x ^{3}}

f (x) = x^{2} - \frac{1}{x}, (- 1, 0)

\int_{0}^{2} \frac{x + 2}{x - 4} d x

x^{\frac{2}{3}}

\frac{d}{d x} ((x^{3} + 2 x)^{37})

\frac{\partial}{\partial y} (x^{3} y^{4} + x^{4} y^{3})

What is the derivative of 4/(3x^2) ?
The derivative of 4/(3x^2) is -8/(3x^3)
What is the first derivative of 4/(3x^2) ?
The first derivative of 4/(3x^2) is -8/(3x^3)