What is implicit (dy)/(dx),xy+4=x ?

The answer to implicit (dy)/(dx),xy+4=x is (dy}{dx}=\frac{1-y)/x

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implicit (dy)/(dx),xy+4=x

implicit derivative

\frac{d y}{d x}, x y + 4 = x

\frac{d y}{d x} = \frac{1 - y}{x}

Solution steps

x y + 4 = x

Treat

y

y (x)

Differentiate both sides:

x \frac{d y}{d x} + y = 1

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = \frac{1 - y}{x}

\frac{d y}{d x} = \frac{1 - y}{x}

x^{2} \frac{d y}{d x} = y - x y, y (- 1) = - 6

\int_{0}^{1} \frac{1}{x ^{0.3}} d x

\frac{d}{d x} (\frac{x + 1}{2 x + 5})

x \to 0 + lim (\frac{( 36 - 4 x ^{2} )}{x})

\frac{d}{d x} (10 sec^{2} (x))

What is implicit (dy)/(dx),xy+4=x ?
The answer to implicit (dy)/(dx),xy+4=x is (dy}{dx}=\frac{1-y)/x