What is the tangent of 5x^2+2x-3 ?

The tangent of 5x^2+2x-3 is y=(10a_{0}+2)x-5a_{0}^2-3

Popular >

tangent of 5x^2+2x-3

tangent of

5 x^{2} + 2 x - 3

y = (10 a_{0} + 2) x - 5 a_{0}^{2} - 3

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 5 a_{0}^{2} + 2 a_{0} - 3)

Find the slope of

y = 5 x^{2} + 2 x - 3 : \frac{d y}{d x} = 10 x + 2

Compute the slope of

y = 5 x^{2} + 2 x - 3

x = a_{0} : m = 10 a_{0} + 2

Find the line with slope m=

10 a_{0} + 2

and passing through

(a_{0}, 5 a_{0}^{2} + 2 a_{0} - 3) : y = (10 a_{0} + 2) x - 5 a_{0}^{2} - 3

y = (10 a_{0} + 2) x - 5 a_{0}^{2} - 3

y^{^{'}} = \frac{x ^{2} \cdot e ^{(\frac{y}{x})} + y ^{2}}{x \cdot y}

x \to 2 lim (x^{2} - 4 x + 4)

y^{^{''}} + 10 y^{^{'}} + 25 y = 0, y (1) = 0, y^{^{'}} (1) = 1

x \to 1 lim (- 1.6 x + 0.6)

\int \frac{1}{x ln ( 3 x )} d x

What is the tangent of 5x^2+2x-3 ?
The tangent of 5x^2+2x-3 is y=(10a_{0}+2)x-5a_{0}^2-3