What is the integral of (sin(x))/4 ?

The integral of (sin(x))/4 is -1/4 cos(x)+C

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integral of (sin(x))/4

\int \frac{sin ( x )}{4} d x

- \frac{1}{4} cos (x) + C

Solution steps

\int \frac{sin ( x )}{4} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= \frac{1}{4} (- cos (x))

Simplify

= - \frac{1}{4} cos (x)

Add a constant to the solution

= - \frac{1}{4} cos (x) + C

f (x) = 14 - x, at x = 5

\frac{\partial}{\partial x} (\frac{1}{x} + \frac{1}{y})

\frac{d}{d x} ((4 - x^{\frac{2}{3}})^{\frac{3}{2}})

e^{- 3 x^{2}}

\int \frac{1}{4 t} d t

What is the integral of (sin(x))/4 ?
The integral of (sin(x))/4 is -1/4 cos(x)+C