What is the derivative of f(x)=5x+2x^2+7e^x ?

The derivative of f(x)=5x+2x^2+7e^x is 5+4x+7e^x

What is the first derivative of f(x)=5x+2x^2+7e^x ?

The first derivative of f(x)=5x+2x^2+7e^x is 5+4x+7e^x

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derivative of

f (x) = 5 x + 2 x^{2} + 7 e^{x}

5 + 4 x + 7 e^{x}

Solution steps

\frac{d}{d x} (5 x + 2 x^{2} + 7 e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (5 x) + \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (7 e^{x})

\frac{d}{d x} (5 x) = 5

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (7 e^{x}) = 7 e^{x}

= 5 + 4 x + 7 e^{x}

y = - x^{2} + 1, y = 0

\int_{0}^{π} \frac{1}{π - x} d x

x \to - \frac{5}{2} lim (- x + 2)

\frac{d}{d x} (cos (x) - 1)

What is the derivative of f(x)=5x+2x^2+7e^x ?
The derivative of f(x)=5x+2x^2+7e^x is 5+4x+7e^x
What is the first derivative of f(x)=5x+2x^2+7e^x ?
The first derivative of f(x)=5x+2x^2+7e^x is 5+4x+7e^x