What is the integral of 3/(\sqrt[4]{x^5)} ?

The integral of 3/(\sqrt[4]{x^5)} is -(12)/(\sqrt[4]{x)}+C

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integral of 3/(\sqrt[4]{x^5)}

Solution steps

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

Apply exponent rule:

(a^{n})^{m} = a^{n \cdot m}

= 3 \cdot \int \frac{1}{x ^{\frac{5}{4}}} d x

Apply the Power Rule

Simplify

Add a constant to the solution

x \to 3 lim (x^{2} + 2 x - 10)

y^{^{''}} + 17 y = 0

\int \frac{x ^{7}}{1 + x ^{16}} d x

(sin (y))^{^{'}}

y = \frac{x}{x + 4}, (1, 0.2)

What is the integral of 3/(\sqrt[4]{x^5)} ?
The integral of 3/(\sqrt[4]{x^5)} is -(12)/(\sqrt[4]{x)}+C