What is the derivative of \sqrt[3]{t^2}-5sqrt(t^3) ?

The derivative of \sqrt[3]{t^2}-5sqrt(t^3) is (2t}{3(t^2)^{2/3}}-\frac{15sqrt(t))/2

What is the first derivative of \sqrt[3]{t^2}-5sqrt(t^3) ?

The first derivative of \sqrt[3]{t^2}-5sqrt(t^3) is (2t}{3(t^2)^{2/3}}-\frac{15sqrt(t))/2

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derivative of

\frac{2 t}{3 ( t ^{2} ) ^{\frac{2}{3}}} - \frac{15 t}{2}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d t} (5 t^{3}) = \frac{15 t}{2}

= \frac{2 t}{3 ( t ^{2} ) ^{\frac{2}{3}}} - \frac{15 t}{2}

\frac{d y}{d x} + 3 x y^{3} = 0, y (0) = 1

\int \frac{5 e ^{2 x} - e ^{x}}{e ^{2 x} - 1} d x

\frac{\partial}{\partial x} (9 x^{2} y^{2})

\int (x^{2} e^{2 x} - 3 x e^{2 x} + 5 e^{2 x}) d x

\int_{2}^{6} 8 d x

What is the derivative of \sqrt[3]{t^2}-5sqrt(t^3) ?
The derivative of \sqrt[3]{t^2}-5sqrt(t^3) is (2t}{3(t^2)^{2/3}}-\frac{15sqrt(t))/2
What is the first derivative of \sqrt[3]{t^2}-5sqrt(t^3) ?
The first derivative of \sqrt[3]{t^2}-5sqrt(t^3) is (2t}{3(t^2)^{2/3}}-\frac{15sqrt(t))/2