What is the integral from 1 to 8 of x^{-2/3} ?

The integral from 1 to 8 of x^{-2/3} is 3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 8 of x^{-2/3}

\int_{1}^{8} x^{- \frac{2}{3}} d x

3

Solution steps

\int_{1}^{8} x^{- \frac{2}{3}} d x

Apply the Power Rule

: [3 x^{\frac{1}{3}}]_{1}^{8}

= [3 x^{\frac{1}{3}}]_{1}^{8}

Compute the boundaries:

3

= 3

\int \frac{36 - x ^{2}}{x ^{2}} d x

f (x) = \frac{x ^{2} 3 x}{6}

\int a e^{a x} (2 + a x) d x

\frac{d y}{d x} = sin (19 x)

\int_{4}^{5} t t - 4 d t

What is the integral from 1 to 8 of x^{-2/3} ?
The integral from 1 to 8 of x^{-2/3} is 3