What is the solution for 3e^{4x}y^'=-16 x/(y^2),y(0)=1 ?

The solution for 3e^{4x}y^'=-16 x/(y^2),y(0)=1 is y=\sqrt[3]{4xe^{-4x}+e^{-4x}}

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3e^{4x}y^'=-16 x/(y^2),y(0)=1

3 e^{4 x} y^{^{'}} = - 16 \frac{x}{y ^{2}}, y (0) = 1

Solution steps

3 e^{4 x} y^{'} (x) = - 16 \frac{x}{y ^{2}}

Solve separable ODE:

\frac{\partial}{\partial y} (\frac{y ^{4}}{x})

\frac{d}{d s} (s + t)

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x \to - 6 - lim (\frac{1}{( x + 6 ) ^{4}})

What is the solution for 3e^{4x}y^'=-16 x/(y^2),y(0)=1 ?
The solution for 3e^{4x}y^'=-16 x/(y^2),y(0)=1 is y=\sqrt[3]{4xe^{-4x}+e^{-4x}}